The general solution of the differential equation $\frac{dy}{dx} + \frac{y \ln y}{x} = \frac{y(\ln y)^2}{x^2}$ is (where $C$ is an arbitrary constant):

  • A
    $\ln y = \frac{1}{2x} + Cx$
  • B
    $\frac{1}{\ln y} = \frac{1}{2x} + C$
  • C
    $\frac{1}{\ln y} = \frac{1}{2x} + Cx$
  • D
    $\ln y = \frac{1}{x} + Cx$

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